/Python/Sorting a dictionary by value in python

Sorting a dictionary by value in python

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sorting a dictionary by value in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

Similar codes

0 vote142 views1 answer
Django form custom validation
Python
12 votes138 views6 answers
Pandas drop duplicates
Python
0 vote184 views1 answer
Genrate random code in django
Python Django
3 votes138 views1 answer
Python read file in string list
Python
0 vote140 views1 answer
Numpy mask without losing shape
Python
0 vote154 views1 answer
Multi hot encode pandas column
Python
0 vote138 views1 answer
%%writefile jupyter notebook
Python
0 vote170 views1 answer
ID number zero python
Python
0 vote136 views1 answer
Protocol buffers python
Python
6 votes154 views6 answers
Tuple methods in python
Python