/Python/Sorting a dictionary by value in python

Sorting a dictionary by value in python

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sorting a dictionary by value in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

Similar codes

0 vote180 views1 answer
Pandas crosstab function(counting) frequencies
Python
0 vote214 views1 answer
Smart Weather Information App Using Python
Python
1 vote225 views1 answer
How to make a discord bot dm someone python
Python
0 vote270 views1 answer
Simulate robot arm using python
Python
30 votes194 views3 answers
Console log heroku
Python
21 votes199 views6 answers
Python simple server
Python
-1 vote210 views1 answer
Calculate quantiles python
Python
-1 vote192 views1 answer
Get the largest of 2 strings python
Python
22 votes194 views4 answers
Python count appearances in list
Python
0 vote187 views1 answer
Pyodbc cursor create list of dictionaries
Python