Sort a list of array python

from operator import itemgetter
A = [[10, 8], [90, 2], [45, 6]]
print("Sorted List A based on index 0: % s" % (sorted(A, key=itemgetter(0))))
B = [[50, 'Yes'], [20, 'No'], [100, 'Maybe']]
print("Sorted List B based on index 1: % s" % (sorted(B, key=itemgetter(1))))

"""
Output:
Sorted List A based on index 0: [[10, 8], [45, 6], [90, 2]]
Sorted List B based on index 1: [[100, 'Maybe'], [20, 'No'], [50, 'Yes']]
"""

Source: delftstack.com

How to sort a list in python

l=[1,3,2,5]
l= sorted(l)
print(l)
#output=[1, 2, 3, 5]
#or reverse the order:
l=[1,3,2,5]
l= sorted(l,reverse=True)
print(l)
#output=[5, 3, 2, 1]

Similar codes

0 vote173 views1 answer
E: Package 'python-certbot-nginx' has no installation candidate
Python
0 vote177 views2 answers
Qq plot using seaborn with regression line
Python
-1 vote182 views1 answer
Opencv python rgb to hsv
Python
1 vote234 views2 answers
How to find 1 st digit in python
Python
0 vote171 views1 answer
Sending email in django
Python
0 vote187 views1 answer
Python censoring pypi
Python
0 vote188 views1 answer
Python session set cookies
Python
8 votes197 views3 answers
Np.arrange
Python
0 vote204 views1 answer
How to config django templates with pathlib
Python
7 votes178 views3 answers
Python get file extension from path
Python