/Java/Compare two character alphabetically java

Compare two character alphabetically java

Java compare strings alphabetically

String a = "HYRE"; 
String b = "AGNYG";  

int compare = a.compareTo(b);  

if (compare < 0) {  
    //a is smaller
}
else if (compare > 0) {
    //a is larger 
}
else {  
    //a is equal to b
}

Compare two character alphabetically java

return Character.toLowerCase(ch1) < Character.toLowerCase(ch2);

Source: stackoverflow.com

Similar codes

1 vote157 views1 answer
How to get path of captured image in android
Java
10 votes150 views4 answers
How to find sha key in android studio
Java
0 vote142 views1 answer
Can the method local inner class object access method local variables
Java
1 vote152 views2 answers
Camel java
Java
0 vote154 views1 answer
Hashmap get value by key java
Java
2 votes159 views1 answer
Link to method javadoc
Java
1 vote170 views1 answer
Admost track purchase
Java
0 vote188 views2 answers
Spring boot rest api
Java Spring
3 votes147 views2 answers
Arraylist methods in java
Java
6 votes164 views4 answers
Install java on ubuntu 20.04
Java