Python random phone number

import random

def phn():
    n = '0000000000'
    while '9' in n[3:6] or n[3:6]=='000' or n[6]==n[7]==n[8]==n[9]:
        n = str(random.randint(10**9, 10**10-1))
    return n[:3] + '-' + n[3:6] + '-' + n[6:]

Source: stackoverflow.com

Similar codes

4 votes149 views5 answers
Epoch to datetime python
Python
0 vote147 views1 answer
Frozen graph can't be modified
Python
0 vote149 views3 answers
How to print a text in python
Python
0 vote160 views1 answer
Assert var == 0
Python
1 vote142 views1 answer
Python launch file
Python
1 vote138 views1 answer
Python condition if dataype
Python
0 vote162 views1 answer
Numpy randomly swap lines
Python
10 votes157 views4 answers
How to make a variable in python
Python
0 vote134 views1 answer
How to plot stacked bar chart from grouped data pandas
Python
0 vote133 views1 answer
Solve system of linear equations numpy
Python