Python random phone number

import random

def phn():
    n = '0000000000'
    while '9' in n[3:6] or n[3:6]=='000' or n[6]==n[7]==n[8]==n[9]:
        n = str(random.randint(10**9, 10**10-1))
    return n[:3] + '-' + n[3:6] + '-' + n[6:]

Source: stackoverflow.com

Similar codes

2 votes244 views2 answers
Django and operator
Python Django
21 votes193 views5 answers
Python stop script
Python
2 votes222 views2 answers
Get query param in django
Python Django
2 votes177 views1 answer
How to represent equation in Pytho
Python
0 vote200 views2 answers
Remove leading and lagging spaces dataframe python
Python
0 vote258 views1 answer
Lose your django secret key
Python Django
1 vote163 views1 answer
Django celery results
Python
0 vote188 views1 answer
Image from wikipedia module in python
Python
19 votes140 views2 answers
Install selenium python
Python
0 vote176 views1 answer
Mean along third dimension array python
Python