/Python/Sort a dictionary by value then key

Sort a dictionary by value then key

Sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

4

Source: stackoverflow.com

Python sort the values in a dictionaryi

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

2

Sort a dictionary by value then key

d = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}
[v[0] for v in sorted(d.items(), key=lambda kv: (-kv[1], kv[0]))]

0

Source: stackoverflow.com

Similar codes

0 vote221 views1 answer
How to create decorator function in django
Python Django
2 votes177 views1 answer
Tkinter execute function on enter
Python
2 votes213 views1 answer
Django mysql
Python Django
0 vote161 views2 answers
Jsonresponse status code django
Python
82 votes189 views6 answers
Arch Linux
Python
0 vote202 views1 answer
Make a pong game in python
Python
25 votes213 views6 answers
Python check if list contains elements of another list
Python
0 vote286 views2 answers
How to close a flask web server with python
Python Flask
16 votes177 views3 answers
Pandas open text file
Python
2 votes197 views1 answer
Django.core.exceptions.ImproperlyConfigured
Python

Share