/Python/Sort a dictionary by value then key

Sort a dictionary by value then key

Sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

4

Source: stackoverflow.com

Python sort the values in a dictionaryi

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

2

Sort a dictionary by value then key

d = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}
[v[0] for v in sorted(d.items(), key=lambda kv: (-kv[1], kv[0]))]

0

Source: stackoverflow.com

Similar codes

1 vote177 views3 answers
Django reverse
Python Django
3 votes154 views3 answers
Python iterar claves
Python
0 vote191 views1 answer
Django raise 404
Python Django
23 votes140 views4 answers
Flatten a list of list python
Python
1 vote154 views1 answer
Export python pandas dataframe as json file
Python
1 vote146 views1 answer
Rfind() in python
Python
1 vote185 views1 answer
User matching query does not exist. django
Python Django
1 vote153 views1 answer
Python not jump next line
Python
0 vote148 views1 answer
Split() vs split(' ')
Python
0 vote172 views1 answer
You will be passed a file path P and string S on the command line. Output the number of times the string S appears in the file P.
Python

Share