/Python/Sort a dictionary by value then key

Sort a dictionary by value then key

Sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

4

Source: stackoverflow.com

Python sort the values in a dictionaryi

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

2

Sort a dictionary by value then key

d = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}
[v[0] for v in sorted(d.items(), key=lambda kv: (-kv[1], kv[0]))]

0

Source: stackoverflow.com

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