/Python/Python get command line arguments

Python get command line arguments

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

Source: pythonforbeginners.com

Pass argument to a py file

import sys

def hello(a,b):
    print "hello and that's your sum:", a + b

if __name__ == "__main__":
    a = int(sys.argv[1])
    b = int(sys.argv[2])
    hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"

Java read file from command line argument

import java.util.Scanner;
import java.io.File;
Scanner input = new Scanner(new File(args[0])); //Where args[0] is the cmd argument, the file name

Similar codes

1 vote135 views1 answer
Python cmath constants
Python
0 vote141 views1 answer
Python check column conditions
Python
0 vote102 views1 answer
How to iterate a dictionary with minimum value in python
Python
0 vote98 views1 answer
Pandas loop through unique values
Python
0 vote141 views1 answer
City in ontario with cheapest houses
Python
7 votes194 views4 answers
Pandas.get_dummies
Python
0 vote135 views1 answer
Turn numpy function into tensorflow
Python
1 vote138 views1 answer
Koncemzem
Python
1 vote193 views3 answers
Exponential python
Python
0 vote140 views1 answer
Hide password in python
Python