/Python/Streamlit - Warning: NumberInput value below has type int so is displayed as int despite format string %.1f.

Streamlit - Warning: NumberInput value below has type int so is displayed as int despite format string %.1f.

import streamlit as st
st.number_input(label="float displayed as integer", format="%i", value=2.4)

# The solution for the waring here is to use format="%i" instead of format="%0f"

# Moreover, here below some options we can use with st.number_input()
prior_variance = st.sidebar.number_input(
label=“Prior Variance”,
min_value=0.00,
value=0.027,
step=0.01,
format="%i",,
)

Source: github.com

Similar codes

0 vote202 views1 answer
Scikit normalize
Python
3 votes211 views1 answer
How do you print a integer in python
Python
0 vote185 views1 answer
Minio python make an object
Python
2 votes139 views1 answer
How to plus numbers in strings
Python
1 vote268 views1 answer
Replace none with empty string python
Python
2 votes178 views1 answer
Python typing as int or float
Python
0 vote186 views1 answer
How to python string up
Python
24 votes195 views6 answers
Merge two columns pandas
Python
0 vote177 views1 answer
Python tkinter fenstergröße
Python
2 votes169 views2 answers
Remove all rows where one ccolumns egale to nan
Python