Pyramid pattern in python

Pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()

Pyramid pattern in python

n = 3
for i in range(1, n+1):
  print(f"{' '*(n-i)}{' *'*i}"[1:])
  
# Output:
#  *
# * *
#* * *

* pattern by python

def pattern(n):    
  for i in range(0,n):       
    for j in range(0, i+1): 
      print("* " , end="")         
      print("\r") pattern(5

Similar codes

5 votes178 views6 answers
Python 3 cheat sheet
Python
0 vote138 views1 answer
Column names reading csv file python
Python
5 votes160 views1 answer
If statement in one-line for loop python
Python
0 vote97 views1 answer
Timeit command line
Python
0 vote146 views1 answer
Os get directory from string
Python
0 vote125 views1 answer
Webhook logger python
Python
4 votes121 views1 answer
Pandas add dataframe to the bottom of another
Python
0 vote126 views1 answer
Mode of a column in df
Python
4 votes163 views2 answers
Flask get variable from url
Python Flask
0 vote129 views1 answer
K-Means Clustering in Python – 3 clusters
Python