Pyramid pattern in python

Pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()

Pyramid pattern in python

n = 3
for i in range(1, n+1):
  print(f"{' '*(n-i)}{' *'*i}"[1:])
  
# Output:
#  *
# * *
#* * *

* pattern by python

def pattern(n):    
  for i in range(0,n):       
    for j in range(0, i+1): 
      print("* " , end="")         
      print("\r") pattern(5

Similar codes

24 votes133 views3 answers
Tkinter image
Python
5 votes140 views1 answer
Python string replace index
Python
0 vote123 views1 answer
File "script.py", line 1 import module math ^ SyntaxError: invalid syntax
Python
82 votes138 views4 answers
Python object to json file
Python
0 vote175 views2 answers
Box detection
Python
5 votes146 views2 answers
Python windows notification
Python
1 vote168 views1 answer
Xpath helium
Python
22 votes133 views3 answers
How to call a random function in python
Python
0 vote133 views1 answer
How to make a world wide web server python
Python
0 vote126 views1 answer
Matplotlib random color
Python