/Python/Python print exception type and message

Python print exception type and message

Python get exception message

try:
    with open(filepath,'rb') as f:
        con.storbinary('STOR '+ filepath, f)
    logger.info('File successfully uploaded to '+ FTPADDR)
except Exception as e: # work on python 3.x
    logger.error('Failed to upload to ftp: '+ str(e))

Source: stackoverflow.com

Python print exception type and message

# In cases where you need to access exception **type** and message separately
try:
    x = 1/0
except Exception as ex:
  	# In most cases, print(ex) or logging.exception(ex) will do
    # But here we need to format the error message and access its type
    template = "An exception of type '{0}' occurred.\n\tArguments:{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print(message) 

# The lines above print:
    # An exception of type 'ZeroDivisionError' occurred.
    #    Arguments:('division by zero',)

Source: stackoverflow.com

Python get exception message

try:
  # do something
  pass
except:
  # this will print the message "An exception occurred and the traceback" 
  # you can't have to explicitly give the message
  logger.exception("An exception occurred")

Similar codes

0 vote102 views2 answers
Python send image server
Python
1 vote107 views1 answer
Random question generator python
Python
3 votes113 views1 answer
How to create a label in tkinter python
Python
0 vote146 views1 answer
How to select the shortest item in a python list
Python
0 vote113 views1 answer
WxPython wx.Window Connect example
Python
0 vote102 views1 answer
Chart-studio python install
Python
3 votes218 views5 answers
India
Python
3 votes110 views1 answer
Python plot cut off when saving figure
Python
0 vote110 views1 answer
Python ceil method
Python
1 vote72 views1 answer
Remove text between brackets python
Python