Pandas index between time

i = pd.date_range('2018-04-09', periods=4, freq='1D20min')
ts = pd.DataFrame({'A': [1, 2, 3, 4]}, index=i)
ts
                     A
2018-04-09 00:00:00  1
2018-04-10 00:20:00  2
2018-04-11 00:40:00  3
2018-04-12 01:00:00  4

ts.between_time('0:15', '0:45')
                     A
2018-04-10 00:20:00  2
2018-04-11 00:40:00  3

You get the times that are not between two times by setting start_time later than end_time:

ts.between_time('0:45', '0:15')
                     A
2018-04-09 00:00:00  1
2018-04-12 01:00:00  4

Source: stackoverflow.com

Similar codes

1 vote118 views1 answer
Chr() function in Python
Python
0 vote153 views1 answer
No module named 'bootstrap4' django
Python Django
0 vote99 views1 answer
How to get values in each cluster
Python
0 vote109 views1 answer
Python counting subfolders on specific level
Python
3 votes120 views3 answers
Python codes
Python
6 votes130 views1 answer
If string is in array python
Python
0 vote104 views1 answer
C++ vs python
Python
0 vote104 views1 answer
System commands in python windwos
Python
2 votes113 views6 answers
Boolean in python
Python
0 vote106 views1 answer
Python string: string concatenation
Python