Hcf program in python

def hcf(x, y):  
   if x > y:  
       smaller = y  
   else:  
       smaller = x  
   for i in range(1,smaller + 1):  
       if((x % i == 0) and (y % i == 0)):  
           hcf = i  
   return hcf  
  
num1 = int(input("Enter first number: "))  
num2 = int(input("Enter second number: "))  
print("The H.C.F. of", num1,"and", num2,"is", hcf(num1, num2))

Source: javatpoint.com

Similar codes

0 vote221 views1 answer
App is not a registered namespace django
Python Django
63 votes150 views3 answers
Iterate through a list
Python
0 vote158 views1 answer
0x80370102 kali linux
Python
0 vote158 views1 answer
Python mysqlclient not installing
Python
0 vote175 views1 answer
Plt text verticalalignment
Python
73 votes142 views1 answer
Pip install error
Python
0 vote155 views1 answer
[ WARN:0] global C:\Users\appveyor\AppData\Local\Temp\1\pip-req-build-wwma2wne\o pencv\modules\videoio\src\cap_msmf.cpp (677) CvCapture_MSMF::initStream Failed t o set mediaType (stream 0, (640x480 @ 30) MFVideoFormat_RGB24(codec not found)
Python
4 votes151 views1 answer
Np array to wav file
Python
0 vote147 views1 answer
Python get part of jason from string
Python
6 votes175 views2 answers
Python check if any elements in a list are different
Python