Hcf program in python

def hcf(x, y):  
   if x > y:  
       smaller = y  
   else:  
       smaller = x  
   for i in range(1,smaller + 1):  
       if((x % i == 0) and (y % i == 0)):  
           hcf = i  
   return hcf  
  
num1 = int(input("Enter first number: "))  
num2 = int(input("Enter second number: "))  
print("The H.C.F. of", num1,"and", num2,"is", hcf(num1, num2))

Source: javatpoint.com

Similar codes

0 vote139 views1 answer
How to install mediapipe python
Python
9 votes288 views6 answers
Python def
Python
0 vote189 views1 answer
Get index of first true value numpy
Python
37 votes138 views6 answers
Count rows with nan pandas
Python
1 vote150 views1 answer
Python time.strptime milliseconds
Python
0 vote141 views1 answer
How to remove last 2 rows in a dataframe
Python
4 votes146 views2 answers
Django template for range
Python
0 vote142 views2 answers
Python creare una list comprehension
Python
-1 vote149 views3 answers
Blockchain.py
Python
0 vote153 views1 answer
Pandas mysql error in query concat with space
Python