Hcf program in python

def hcf(x, y):  
   if x > y:  
       smaller = y  
   else:  
       smaller = x  
   for i in range(1,smaller + 1):  
       if((x % i == 0) and (y % i == 0)):  
           hcf = i  
   return hcf  
  
num1 = int(input("Enter first number: "))  
num2 = int(input("Enter second number: "))  
print("The H.C.F. of", num1,"and", num2,"is", hcf(num1, num2))

Source: javatpoint.com

Similar codes

0 vote193 views1 answer
Pandas assign value to row based on condition
Python
0 vote187 views1 answer
Regex to find ip address python
Python
0 vote209 views1 answer
Load dataset X = pd.DataFrame(data.data, columns=data.features)
Python
2 votes257 views2 answers
Python "for in" loop to print the last item in the list
Python
1 vote190 views1 answer
Error urllib request no attribute
Python
2 votes219 views1 answer
Find all color in image python
Python
0 vote218 views1 answer
How to implement ctrl + C in terminal by using code
Python
0 vote199 views1 answer
Find percentage of missing values in a column in python
Python
0 vote196 views1 answer
Django MESSAGE_TAGS
Python
1 vote226 views1 answer
Django model choice field from another model
Python Django