/TypeScript/How to execute scripts when a button gui is pressed roblox

How to execute scripts when a button gui is pressed roblox

function leftClick()
	print("Left mouse click")
end
 
function rightClick()
	print("Right mouse click")
end
 
script.Parent.MouseButton1Click:Connect(leftClick)
script.Parent.MouseButton2Click:Connect(rightClick)

How to execute scripts when a button gui is pressed roblox

2022-02-03 00:00:07 18334/18334 D/PretiumManager: [doLoadLocalStatusSync] from = X8Application_onCreate_loadLocalStatusSync, file = /data/user/0/com.x8zs.sandbox/files/pretium, file not exist, use none

How to execute scripts when a button gui is pressed roblox

-- Doesnt explain WHERE to put what..-
local buttongui = script.Parent -- (this is only if your script is inside the gui, and really, should be a local script and not a normal one)
local clicked1 = buttongui.MouseButton1Click
local clicked2 = buttongui.MouseButton2Click -- These two variables are useful if you wanna do something more than twice..

function lClick()
  buttongui.Text = "left click"
end

function Rclick()
  buttongui.Text = "right click"
end

clicked1:Connect(lClick)
clicked2:Connect(RClick)

How to execute scripts when a button gui is pressed roblox

THEBUTTON.MouseButton1Down:connect(function()
-- the function
end)
-- this is easy why do many people do it so complicated

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