Set operators

Ops 		P	⨯	 \	 =	 ≠
Front 		⊂	⊄	⊆	⊈	⊊ 
Back 		⊃	⊅	⊇	⊉	⊋
Inside 		∀	∃	∊	∍
Objects 	∅	∞	∆	∇

Set operators

>>> a = {1, 2, 3, 4, 5, 6}
>>> b = {4, 5, 6, 7, 8, 9}
>>>
>>> a.update(b)          # a "union" operation
>>> a
{1, 2, 3, 4, 5, 6, 7, 8, 9}
>>>
>>> a &= b               # the "intersection" operation
>>> a
{4, 5, 6, 7, 8, 9}
>>>
>>> a -= set((7, 8, 9))  # the "difference" operation
>>> a
{4, 5, 6}
>>>
>>> a ^= b               # the "symmetric difference" operation
>>> a
{7, 8, 9}

Source: freecodecamp.org

Similar codes

1 vote128 views1 answer
Slicing lexicographically pandas
Python
0 vote166 views1 answer
Import pil pycharm
Python
13 votes118 views3 answers
Pandas set a value in colmns as the maximum value
Python
0 vote184 views1 answer
How to find the medium, first, second and third quartile in a pandas data frame
Python
0 vote131 views1 answer
Arithmetic encoding python
Python
1 vote163 views1 answer
Get current site django
Python Django
-1 vote136 views1 answer
Dataframe partition dataset based on column
Python
27 votes125 views6 answers
Create a empty dataframe
Python
3 votes149 views2 answers
Dict get list of values
Python
3 votes151 views3 answers
Simple jwt django
Python Django