/Python/Flask/Flask arguments in url

Flask arguments in url

Get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

4

Source: stackoverflow.com

Flask arguments in url

@app.route('/<name>')
def my_view_func(name):
    return name

0

Source: stackoverflow.com

Similar codes

3 votes139 views1 answer
Flask give port number
Python Flask
0 vote188 views1 answer
Flask request file push request(uploadedfile= request.file) uploadedfile.read()
Python Flask
1 vote147 views1 answer
Posted data to flask
Python Flask
0 vote144 views1 answer
Flask wtforms multiple select
Python Flask
1 vote89 views1 answer
Procfile for flask app
Python Flask
0 vote133 views2 answers
Flask heroku
Python Flask
0 vote134 views1 answer
Flask decoding base 64 image
Python Flask
1 vote137 views2 answers
Flask bootstrap
Python Flask
0 vote138 views1 answer
From flask_paginate import get_page_parameter
Python Flask
2 votes140 views2 answers
Flask 'export' is not recognized as an internal or external command, operable program or batch file.
Python Flask

Share