Python chunks

Python split range equally

def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):
        yield lst[i:i + n]
        
list(chunks(range(10, 75), 10))

Split list into lists of equal length python

[lst[i:i + n] for i in range(0, len(lst), n)]

Source: stackoverflow.com

Python chunks

//e//sere/dsads/fdfd/sf/sdfs/fd/fds/fd/afd/sfd/sf/sfd/s/fs/fs/fd

Similar codes

7 votes155 views2 answers
Python print dict pretty
Python
0 vote171 views1 answer
Pandas increment value on condition
Python
0 vote142 views1 answer
Check django channels with redis setup
Python
1 vote176 views2 answers
Changing the number of ticks on a Matplotlib plot axis
Python
1 vote151 views1 answer
How to use datetime to tell your age in python
Python
0 vote136 views1 answer
Nunique sort
Python
-1 vote149 views1 answer
Python design patterns
Python
0 vote162 views1 answer
Prefetched_related django rest framework
Python
0 vote208 views1 answer
Python sort list alpha
Python
0 vote174 views1 answer
Instead of: newlist = [] for i in range(1, 100): if i % 2 == 0: newlist.append(i**2)
Python