How to print value of pointer in c

#include <stdio.h>
#include <stdlib.h>

void pointerFuncA(int* iptr){
/*Print the value pointed to by iptr*/
printf("Value:  %d\n", *iptr );

/*Print the address pointed to by iptr*/
printf("Value:  %p\n", iptr );

/*Print the address of iptr itself*/
printf("Value:  %p\n", &iptr );
}

int main(){
int i = 1234; //Create a variable to get the address of
int* foo = &i; //Get the address of the variable named i and pass it to the integer pointer named foo
pointerFuncA(foo); //Pass foo to the function. See I removed void here because we are not declaring a function, but calling it.

return 0;
}

Source: stackoverflow.com

Similar codes

0 vote216 views1 answer
Java Node<E>
C
0 vote213 views2 answers
Int to void* c
C
2 votes200 views1 answer
C include uint8_t
C
0 vote258 views1 answer
Bp result system
C
3 votes283 views1 answer
Insert random numbers in excel
C
22 votes249 views2 answers
C bind str and int
C
2 votes220 views2 answers
C %s
C
0 vote226 views1 answer
Until command lldb
C
2 votes219 views2 answers
Increment and decrement operator
C
0 vote251 views1 answer
Bitwise Operators in C language
C