Wait group golang

Golang waitgroup

package main

import (
    "fmt"
    "sync"
    "time"
)

func worker(id int) {
    fmt.Printf("Worker %d starting\n", id)

    time.Sleep(time.Second)
    fmt.Printf("Worker %d done\n", id)
}

func main() {

    var wg sync.WaitGroup

    for i := 1; i <= 5; i++ {
        wg.Add(1)

        i := i

        go func() {
            defer wg.Done()
            worker(i)
        }()
    }

    wg.Wait()

}

Source: gobyexample.com

Golang waitgroup

var wg sync.WaitGroup

for i := 1; i <= 5; i++ {
	wg.Add(1)
	go func(wg *sync.WaitGroup) {
		wg.Done()
	}()
}

wg.Wait()

Wait group golang

package main

	

import (
    "fmt"
    "sync"
    "time"
)

func worker(id int, wg *sync.WaitGroup) {
    defer wg.Done()
    fmt.Printf("Worker %d starting\n", id)
    time.Sleep(time.Second)
    fmt.Printf("Worker %d done\n", id)
}

	

func main() {
    var wg sync.WaitGroup
    for i := 1; i <= 5; i++ {
        wg.Add(1)
        go worker(i, &wg)
    }
    wg.Wait()
}

Similar codes

1 vote178 views1 answer
Printing byte slice to hexadecimal string in golang
Go
1 vote177 views1 answer
Golang wait for goroutine to finish
Go
0 vote172 views1 answer
How to colorize the output of printf in golang
Go
0 vote175 views1 answer
Www.classroom.com google
Go
0 vote142 views1 answer
How to gab the users imput
Go
5 votes163 views3 answers
Format string go
Go
0 vote174 views1 answer
Code:403 google sheet api
Go
0 vote188 views1 answer
Projection on image from camera in godot
Go
0 vote185 views1 answer
Function change(cash) { // Your code goes here return { two: 0, five: 0, ten: 0 }; }
Go
0 vote165 views1 answer
Go concurrent execution of f with parameter i. Tasks are independent and don't return any value.
Go