Php json_decode not working

Php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Php decode json object

<?php

$json = '{"firstName":"Peter","lastName:":"Silva","age":23}';

$personInfo = json_decode(json);

echo $personInfo->age;

?>

Php try to decode json

/** Checks if JSON and returns decoded as an array, if not, returns false, 
but you can pass the second parameter true, if you need to return
a string in case it's not JSON */
function tryJsonDecode($string, $returnString = false) {
   $arr = json_decode($string);
  if (json_last_error() === JSON_ERROR_NONE) {
    return $arr;
  } else {
    return ($returnString) ? $string : false;
  }
}

Php json_decode not working

You have to use preg_replace for avoiding the null results from json_decode

here is the example code

$json_string = stripslashes(html_entity_decode($json_string));
$bookingdata =  json_decode( preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $json_string), true );

Source: stackoverflow.com

Similar codes

0 vote133 views1 answer
How to stop message of laravel mix
PHP
-1 vote151 views1 answer
Laravel merge two arrays helper
PHP Laravel
1 vote136 views1 answer
Create controller codeigniter 3
PHP
7 votes126 views1 answer
Unable to read key from file file
PHP
1 vote134 views2 answers
Add laravel sail build as alias
PHP
0 vote133 views1 answer
Keep track of view count php
PHP
6 votes135 views2 answers
Php is divisible by
PHP
0 vote94 views1 answer
Laravel collection tap
PHP
13 votes151 views5 answers
Target class [Controller] does not exist.
PHP
0 vote255 views1 answer
Bring up the power shell console php
PHP