/Python/Flask conditional according to urrl

Flask conditional according to urrl

<!DOCTYPE html>
<html>
<head>
    <title>Template</title>
</head>
<body>
    <h3>You are here: {{ request.path }}</h3>
    {% if request.path == url_for('show_funding') %}
        <script src="{{ url_for ('static', filename='js/funding.js')}}"></script>
    {% endif %}
</body>
</html>

Source: stackoverflow.com

Flask conditional according to urrl

from flask import Flask
from flask import request
from flask import render_template

app = Flask(__name__)

@app.route('/')
def show_index():
    return render_template('funding.html')

@app.route('/funding')
def show_funding():
    return render_template('funding.html')

if __name__ == '__main__':
    app.run(debug = True)

Source: stackoverflow.com

Similar codes

5 votes136 views2 answers
My django template doesnt want to load the static file
Python
0 vote130 views1 answer
Python if in list multiple
Python
2 votes150 views1 answer
Python dictionary multiple same keys
Python
0 vote132 views1 answer
Create new column with mask pandas
Python
0 vote156 views1 answer
Add timestamp csv python
Python
1 vote136 views1 answer
How to read zip csv file in python
Python
0 vote142 views1 answer
Pytorch dataloader to numpy array
Python
1 vote139 views1 answer
How tyo make a constantly adding variable in python
Python
21 votes129 views1 answer
Plot x y graph python
Python
0 vote141 views1 answer
Cache_data = pickle.load(fIn) EOFError: Ran out of input
Python