/Python/Flask conditional according to urrl

Flask conditional according to urrl

<!DOCTYPE html>
<html>
<head>
    <title>Template</title>
</head>
<body>
    <h3>You are here: {{ request.path }}</h3>
    {% if request.path == url_for('show_funding') %}
        <script src="{{ url_for ('static', filename='js/funding.js')}}"></script>
    {% endif %}
</body>
</html>

Source: stackoverflow.com

Flask conditional according to urrl

from flask import Flask
from flask import request
from flask import render_template

app = Flask(__name__)

@app.route('/')
def show_index():
    return render_template('funding.html')

@app.route('/funding')
def show_funding():
    return render_template('funding.html')

if __name__ == '__main__':
    app.run(debug = True)

Source: stackoverflow.com

Similar codes

-3 votes133 views5 answers
Multiplication table in python
Python
0 vote147 views2 answers
How to get a specific field in django
Python
21 votes211 views4 answers
Send dm discord py
Python
0 vote119 views1 answer
Pytorch multiply tensors element by elementwise
Python
3 votes126 views3 answers
AttributeError: 'Timedelta' object has no attribute 'minutes'
Python
9 votes109 views1 answer
Cv2.cvtcolor grayscale
Python
0 vote117 views1 answer
Shotgun filter any
Python
0 vote158 views1 answer
Flask development mode
Python
1 vote89 views1 answer
Key down python
Python
0 vote134 views1 answer
Find number of unique keys in the dictionary
Python