/Shell/Bash/Printing arguments in a script

Printing arguments in a script

Printing arguments in a script

#!/bin/bash

# example of using arguments to a script
echo "arg 1: $1"
echo "arg 2: $2"
echo "Total number of arguments is $#"

0

Source: macs.hw.ac.uk

Similar codes

18 votes198 views2 answers
How to get current git branch
Shell/Bash
6 votes192 views1 answer
How to find and replace a string in a file using shell script
Shell/Bash
1 vote199 views1 answer
Gatsby image
Shell/Bash
4 votes280 views3 answers
Error: Your local changes to the following files would be overwritten by checkout:
Shell/Bash
3 votes184 views1 answer
Ngx-material-file-input
Shell/Bash
0 vote191 views4 answers
Empty a file linux
Shell/Bash
0 vote226 views1 answer
How to keep track of github profile views
Shell/Bash
0 vote190 views1 answer
Winbuilder
Shell/Bash
0 vote191 views1 answer
Purge apache 2
Shell/Bash
0 vote197 views1 answer
Codition in bash
Shell/Bash

Share