/SQL/Characters found after end of sql statement

Characters found after end of sql statement

Most likely need to replace the html char code (ex. '&lt;' with actual characters (ex. <) and try it again.

Source: superuser.com

Characters found after end of sql statement

    SQL_Output = "SELECT TblTcAOG.ID, TblTcAOG.Date, TblTcAOG.STN, TblTcAOG.REG, TblTcAOG.ATA, TblTcAOG.[ATA2Digit Description], TblTcAOG.ATA4DIGIT, TblTcAOG.ATA2DIGIT, TblTcAOG.ATALAST2, TblTcAOG.[REASON FOR AOG], TblTcAOG.[AOG HRS], TblTcAOG.[AOG MINS], TblTcAOG.AOGTime, TblTcAOG.AOGTotalMins, TblTcAOG.[Event Type], TblTcAOG.[Severity Index], TblTcAOG.[Dispatched IAW MEL], TblTcAOG.[MEL Reference], TblTcAOG.[ETOPS Sector], TblTcAOG.[Charter Flight], tblactype.actypeid, tblactype.Manufacturer, tblactype.Type " & _
                 "FROM (tblactype INNER JOIN TblAcrft ON tblactype.[actypeid] = TblAcrft.[ModelLink]) INNER JOIN TblTcAOG ON TblAcrft.[Reg] = TblTcAOG.[REG]; " & _
                 "WHERE ((TblTcAOG.Date)>=" & dStart & " And (TblTcAOG.Date)<=" & dEnd & " AND ((TblTcAOG.AOGTotalMins)>=[forms]![FrmRptCriteriaAOG]![AOG_Time])) "

Source: access-programmers.co.uk

Characters found after end of sql statement

SELECT TblTcAOG.ID, TblTcAOG.Date, TblTcAOG.STN, TblTcAOG.REG, TblTcAOG.ATA, TblTcAOG.[ATA2Digit Description], TblTcAOG.ATA4DIGIT, TblTcAOG.ATA2DIGIT, TblTcAOG.ATALAST2, TblTcAOG.[REASON FOR AOG], TblTcAOG.[AOG HRS], TblTcAOG.[AOG MINS], TblTcAOG.AOGTime, TblTcAOG.AOGTotalMins, TblTcAOG.[Event Type], TblTcAOG.[Severity Index], TblTcAOG.[Dispatched IAW MEL], TblTcAOG.[MEL Reference], TblTcAOG.[ETOPS Sector], TblTcAOG.[Charter Flight], tblactype.actypeid, tblactype.Manufacturer, tblactype.Type FROM (tblactype INNER JOIN TblAcrft ON tblactype.[actypeid] = TblAcrft.[ModelLink]) INNER JOIN TblTcAOG ON TblAcrft.[Reg] = TblTcAOG.[REG]; WHERE ((TblTcAOG.Date)>=#04/11/2015# And (TblTcAOG.Date)<=#04/11/2019# AND ((TblTcAOG.AOGTotalMins)>=[forms]![FrmRptCriteriaAOG]![AOG_Time])) AND TblTcAOG.[ATA2DIGIT] IN (0,20,21,12,11,10,09,08,07,06,05,24,25,26,27,28,29,30,31,32,33,22,23,34,35,36,38,47,46,49,51,52,53,54,55,56,57,70,71,72,73,74,75,76,77,78,79,80,01,02,03,04)

Source: access-programmers.co.uk

Similar codes

0 vote142 views1 answer
Sql gap missing values
SQL
1 vote165 views1 answer
Sqlite update from another table
SQL
0 vote137 views1 answer
FIND AVERAGE SALARY EARNER IN SQL
SQL
0 vote107 views1 answer
Deleted table in sql trigger
SQL
1 vote171 views3 answers
Postgresql get difference between two dates
SQL
2 votes198 views2 answers
Postgres drop column if exists
SQL
1 vote157 views3 answers
How to reset id column in sql server
SQL
0 vote158 views1 answer
System.Data.SqlClient.SqlException: 'Execution Timeout Expired. The timeout period elapsed prior to completion of the operation or the server is not responding.' SqlDataAdapter
SQL
1 vote184 views1 answer
Ora-01109 database not open in oracle 19c
SQL
0 vote143 views1 answer
Postgres : ERROR: division by zero
SQL