Fibonacci

Fibbonacci

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811,

Source: google.com

Fibonacci

# Easy fibonacci exercise
# Method #1
def fibonacci(n):
    # 1th: 0
    # 2th: 1
    # 3th: 1 ...
    if n == 1:
        return 0
    elif n == 2:
        return 1
    else:
        return fibonacci(n - 1) + fibonacci(n - 2)

# Method #2
def fibonacci2(n):
    if n == 0: return 0
    n1 = 1
    n2 = 1
    # (1, n - 2) because start by 1, 2, 3... not 0, 1, 1, 2, 3....
    for i in range(1, n - 2):
        n1 += n2
        n2 = n1 - n2
    return n1


print(fibonacci(13))
# return the nth element in the fibonacci sequence

Fibonacci

f(n) = f(n-1) + f(n-2) 
                                  f(6)
                                   ^
  			                       /\
                f(5)               +                       f(4)
                ^
               /\                   +                        /\
                
        f(4)    +           f(3)                     f(3)    +    f(2)
       ^                       ^                     ^              ^
      /\                       /\                    /\            /\
   
 f(3)   +       f(2)            f(2) +f(1)       f(2) + f(1)   f(1) +  f(0)             
   ^              ^                ^                ^
   /\             /\                /\              /\
    
f(2) + f(1)      f(1) +  f(0)     f(1)+ f(0)       f(1) + f(0)         
  ^
  /\
f(1) +  f(0) 
  
//f(6) = 8   ==>  f(1)*8    f(1) appears 8 times 
 double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));  
  
f(1) == 1;

Fibonacci

def fibonacci(n):
    if n == 0:
        return 0
    elif n == 1:
        return 1
    return fibonacci(n - 1) + fibonacci(n - 2)

Source: dbader.org

Fibonacci

def fibonacci(n):
    if n <= 1:
        return n
    else:
        return fibonacci(n-1) + fibonacci(n-2)

limit = int(input("Insert the number of the values of the series that you would see: "))

for num in range(1, limit+1):
    print(fibonacci(num))

Source: programmareinpython.it

Fibonacci

Each test case will contains a single integer n where n >=1.

Source: codequotient.com

Similar codes

2 votes189 views1 answer
Excel vba delete worksheet if exists
C++
1 vote157 views4 answers
Return function in cpp
C++
1 vote211 views1 answer
How to substract to give a positive outcome in c++
C++
1 vote187 views1 answer
64 bit unsigned integer c++
C++
0 vote157 views1 answer
Estimateaffine3d example c++
C++
1 vote159 views1 answer
Cmake define standard c++
C++
1 vote178 views1 answer
How to lock window resize c++ sfml'
C++
0 vote192 views1 answer
C++ caps lock key
C++
0 vote164 views2 answers
C++ bit shift wrap
C++
1 vote163 views2 answers
Check if number is positive or negative in cpp
C++