/Python/Django/Django load model by name

Django load model by name

from django.apps import apps
user = apps.get_model(app_label='auth', model_name='User')
# Can also support syntax like 'auth.User' passing a single parameter
user = apps.get_model('auth.User')

Source: stackoverflow.com

Similar codes

0 vote284 views5 answers
Django-tool-bar
Python Django
0 vote202 views1 answer
Exception Type: AssertionError Exception Value: Expected a `Response`, `HttpResponse` or `HttpStreamingResponse` to be returned from the view, but received a `<class 'django.db.models.query.QuerySet'>`
Python Django
0 vote172 views1 answer
Difference in django project view and app view
Python Django
0 vote192 views1 answer
Django model registration
Python Django
0 vote178 views1 answer
Create django model field based on another field
Python Django
4 votes183 views2 answers
Loginrequiredmixin django
Python Django
0 vote176 views1 answer
Django bootstrap
Python Django
0 vote190 views1 answer
Django extract array from post matrix
Python Django
1 vote190 views1 answer
Django filter not equal to
Python Django
0 vote166 views1 answer
Sending email in django
Python Django