Swift make enum inspectable

// There is no way to do this. But there is a little workaround.

// Swift 5:
public enum Size: String {
  case small = "small"
  case medium = "medium"
  case large = "large"
}

class SizeView: UIView {
  private var size: Size = .large

  @IBInspectable 
  public var sizeName: String = "large" {
    didSet {
      guard self.sizeName != oldValue else { return }
      self.size = Size(rawValue: self.sizeName)
    }
  }
}

Similar codes

0 vote189 views1 answer
Ios network request
Swift
0 vote246 views1 answer
Swift how to wait in a loop
Swift
0 vote197 views1 answer
Swift 5 uidatepicker display inline
Swift
0 vote204 views1 answer
Error TypeError: Network request failed
Swift
0 vote197 views1 answer
Mac os
Swift
0 vote148 views1 answer
Swift sleep milliseconds
Swift
0 vote183 views1 answer
Prime number or not program in swift basic programs
Swift
0 vote177 views1 answer
AMAZONCONNECT
Swift
0 vote208 views1 answer
.next() enum swift
Swift
0 vote206 views1 answer
Use a compatible library with a minSdk of at most 16, or increase this project's minSdk version to at least 19, or use tools:overrideLibrary="com.google.firebase.firebase_analytics"
Swift