/Python/Django/Django filter word count greater than

Django filter word count greater than

Django filter word count greater than

Item.objects.extra(where=["LENGTH(notes) - LENGTH(REPLACE(notes, ' ', ''))+1 > %s"], params=[25])

0

Source: stackoverflow.com

Similar codes

0 vote172 views1 answer
Extra import on django
Python Django
0 vote155 views1 answer
How to make a nice login django form
Python Django
0 vote168 views1 answer
Django is .get lazy
Python Django
1 vote329 views1 answer
Check if the user is logged in django decorator
Python Django
0 vote175 views1 answer
Django redirect to external url
Python Django
6 votes170 views3 answers
Media url django
Python Django
0 vote172 views1 answer
Custom django password checker
Python Django
0 vote178 views1 answer
Django generate openapi schema command line
Python Django
5 votes181 views2 answers
Django password field
Python Django
16 votes187 views6 answers
Django models
Python Django

Share