/Python/Django/Django create view filter options

Django create view filter options

class FolderForm(forms.ModelForm):
    class Meta:
       model = Folder
       fields = ['name', 'parent']

    def __init__(self, *args, **kwargs):
       user = kwargs.pop('user')
       super(FolderForm, self).__init__(*args, **kwargs)
       self.fields['parent'].queryset = Folder.objects.filter(user=user)

Source: stackoverflow.com

Django create view filter options

class FolderCreate(CreateView):
    template_name = 'Form/folder_create.html'
    form_class = FolderForm

    def get_form_kwargs(self):
        kwargs = super(FolderCreate, self).get_form_kwargs()
        kwargs['user'] = self.request.user
        return kwargs

Source: stackoverflow.com

Similar codes

0 vote151 views1 answer
How to use django-rest-framework-datatables
Python Django
7 votes143 views2 answers
How to generate requirements.txt django
Python Django
0 vote162 views1 answer
Check this id exist in database django
Python Django
5 votes198 views1 answer
Q is not defined pylance django
Python Django
0 vote154 views1 answer
Slug in redirect django
Python Django
5 votes154 views1 answer
How to override save method in django
Python Django
1 vote175 views1 answer
How to multiply in django template
Python Django
14 votes186 views6 answers
Install django
Python Django
16 votes183 views6 answers
Django forms
Python Django
0 vote120 views1 answer
Django iterating through objects
Python Django