Python even or odd

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

Program to find even numbers in python

m = int(input("Enter number"))
if m % 2 == 0:
    print(m,"is an even number")
else:
    print(m,"is an odd number")

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

How to make a python program on odd and even

Number = int(input("Write any number:- "))
Opration = Number%2
if Opration == 0:
    print("it's odd number")
else:
    print("It's even number")

Finding odd even python

number = int(input("Write a number:- "))
if number%2 == 0:
    print("Even number")
else:
    print("odd number")

Python even or odd

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

Similar codes

-1 vote139 views6 answers
List comprehension python
Python
1 vote151 views1 answer
Train,test,dev python
Python
101 votes149 views6 answers
Remove last character from string python
Python
1 vote167 views2 answers
Replace number with string python
Python
-2 votes153 views3 answers
Pyhton
Python
0 vote144 views1 answer
Find the highest id in model django
Python
0 vote124 views1 answer
Longueur liste python
Python
0 vote141 views1 answer
Fix the debug_mode = false django
Python
0 vote138 views1 answer
Pass parameters to a odoo wizard
Python
0 vote131 views1 answer
Add a constant to a list python
Python