Python odd or even

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

How to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

Finding odd even python

number = int(input("Write a number:- "))
if number%2 == 0:
    print("Even number")
else:
    print("odd number")

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Python odd or even

n = int(input("Enter a number: "))
print(["even","odd"][n % 2])

Similar codes

0 vote245 views1 answer
Nltk stop words
Python
0 vote237 views1 answer
Apply with sf
Python
0 vote187 views1 answer
Pydub audiosegment to numpy array
Python
11 votes220 views4 answers
Python get random character from string
Python
20 votes194 views5 answers
List directory in python
Python
0 vote198 views1 answer
How to add phone number to django user model
Python
0 vote196 views1 answer
Pass arguments with apply
Python
0 vote178 views1 answer
Python use negation with maskedarray
Python
5 votes193 views1 answer
Python iteratable with inedx
Python
0 vote203 views1 answer
Assert_series_equal
Python