Python odd or even

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

How to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

Finding odd even python

number = int(input("Write a number:- "))
if number%2 == 0:
    print("Even number")
else:
    print("odd number")

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Python odd or even

n = int(input("Enter a number: "))
print(["even","odd"][n % 2])

Similar codes

18 votes115 views4 answers
Delete n from textpython
Python
0 vote107 views1 answer
Python input byte array
Python
1 vote107 views2 answers
Redirect to the same page django
Python
5 votes123 views2 answers
Stitch two dictionary python
Python
82 votes112 views6 answers
Create virtualenv python3
Python
0 vote127 views1 answer
Python format string with list
Python
2 votes131 views1 answer
How to change button background color while clicked tkinter python
Python
-1 vote108 views2 answers
Python pynput space
Python
1 vote117 views1 answer
Python test if list of dicts has key
Python
0 vote114 views1 answer
Zlib decompress python
Python