Php fetch mysql result as variable

<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
?>

Source: stackoverflow.com

Similar codes

0 vote292 views9 answers
How to form data to another file in php
PHP
2 votes194 views2 answers
Php file_get_contents follow redirect
PHP
1 vote182 views2 answers
Add laravel sail build as alias
PHP
9 votes203 views2 answers
How to write for loop in laravel blade
PHP Laravel
17 votes171 views5 answers
Wordpress debug mode
PHP
0 vote194 views1 answer
No cache hummingbird
PHP
0 vote180 views1 answer
Php get current dir mac
PHP
53 votes184 views6 answers
Laravel where in
PHP
-1 vote166 views1 answer
Nginx php-fpm
PHP
0 vote136 views1 answer
Non utf-8 characters in php
PHP