Php fetch mysql result as variable

<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
?>

Source: stackoverflow.com

Similar codes

0 vote126 views1 answer
Laravel deploy without moving public directory
PHP Laravel
1 vote100 views1 answer
$this
PHP
3 votes114 views1 answer
How to named route resource laravel
PHP Laravel
0 vote102 views1 answer
Laravel use model inside blade
PHP
7 votes118 views3 answers
Wordpress echo the date in post
PHP Wordpress
2 votes102 views2 answers
Nginx reverse proxy nextcloud
PHP
3 votes101 views1 answer
Ian holm
PHP
16 votes101 views6 answers
Laravel group routes
PHP
0 vote102 views1 answer
Add Text Before the Product Title
PHP
0 vote114 views1 answer
Laravel project in css
PHP