/Python/How do you count most frequent item in a list in python

How do you count most frequent item in a list in python

Count most frequent words in list python

from collections import Counter

data_set = "Welcome to the world of Geeks " \
"This portal has been created to provide well written well" \
"thought and well explained solutions for selected questions " \
"If you like Geeks for Geeks and would like to contribute " \
"here is your chance You can write article and mail your article " \
" to contribute at geeksforgeeks org See your article appearing on " \
"the Geeks for Geeks main page and help thousands of other Geeks. " \

# split() returns list of all the words in the string
split_it = data_set.split()

# Pass the split_it list to instance of Counter class.
Counters_found = Counter(split_it)
#print(Counters)

# most_common() produces k frequently encountered
# input values and their respective counts.
most_occur = Counters_found.most_common(4)
print(most_occur)

Source: stackoverflow.com

How do you count most frequent item in a list in python

# most frequent value in a list
test = [1, 2, 3, 4, 2, 2, 3, 1, 4, 4, 4] 
print(max(set(test), key = test.count))

-1

Similar codes

0 vote258 views1 answer
Django data from many to many field in template
Python Django
0 vote268 views1 answer
Pandas combine two data frames with same index and same columns
Python
-1 vote201 views1 answer
Sudo apt-get install python2-pip
Python
0 vote203 views1 answer
Latex maths to python parser
Python
4 votes204 views4 answers
Pandas groupby sum
Python
16 votes151 views1 answer
Add to index python
Python
0 vote189 views1 answer
Django template date format yyyy-mm-dd
Python Django
1 vote224 views1 answer
Python flatten array of arrays
Python
2 votes272 views1 answer
How to get micro symbol in python
Python
1 vote199 views2 answers
Python timedelta to seconds
Python