/Python/Python sort a list by a custom order

Python sort a list by a custom order

# Example usage:
list_to_sort = [('U', 23), ('R', 42), ('L', 17, 'D')]
custom_sort_order = ['R', 'D', 'L', 'U']
sorted(list_to_sort, key=lambda list_to_sort: custom_sort_order.index(list_to_sort[0]))
# Where 0 is the tuple index to use for sorting by custom order
--> [('R', 42), ('L', 17, 'D'), ('U', 23)]

Source: stackoverflow.com

Similar codes

0 vote149 views1 answer
Python __repr__ meaning
Python
0 vote129 views1 answer
Spark.read.load
Python
0 vote168 views1 answer
Copy file merged hdfs
Python
0 vote182 views1 answer
Http404 django
Python Django
0 vote161 views1 answer
Rotate image pyqt5
Python
0 vote179 views1 answer
Statistique in python
Python
0 vote135 views2 answers
Generate random password django
Python
0 vote158 views1 answer
What takes more memory string or list python
Python
0 vote162 views1 answer
Python join list ignore none and empty string
Python
0 vote147 views1 answer
New column with addition of other columns
Python