/Python/How to check if a number is a perfect square python

How to check if a number is a perfect square python

Check if a number is perfect cube in python

x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)

How to check if a number is a perfect square python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python num perfect squares

print(int(int(n)**.5))

Similar codes

21 votes171 views2 answers
Python string does not contain
Python
2 votes182 views2 answers
Conda create jupyter kernel
Python
-1 vote193 views4 answers
Python sort string
Python
0 vote187 views1 answer
KeyError: 'ProfilePage'
Python
19 votes169 views3 answers
Python list with all letters
Python
2 votes184 views4 answers
How to do fibonacci sequence in python
Python
0 vote183 views1 answer
Add an element to list python
Python
14 votes169 views6 answers
Installing django on windows
Python
3 votes178 views1 answer
Blackjack in python
Python
25 votes130 views4 answers
Python pyautogui
Python