/Python/Python extract zip file without directory structure

Python extract zip file without directory structure

Python zip extract directory

import zipfile

archive = zipfile.ZipFile('archive.zip')

for file in archive.namelist():
    if file.startswith('foo/'):
        archive.extract(file, 'destination_path')

Source: stackoverflow.com

Python extract zip file without directory structure

import os
import shutil
import zipfile

my_dir = r"D:\Download"
my_zip = r"D:\Download\my_file.zip"

with zipfile.ZipFile(my_zip) as zip_file:
    for member in zip_file.namelist():
        filename = os.path.basename(member)
        # skip directories
        if not filename:
            continue

        # copy file (taken from zipfile's extract)
        source = zip_file.open(member)
        target = open(os.path.join(my_dir, filename), "wb")
        with source, target:
            shutil.copyfileobj(source, target)

Source: stackoverflow.com

How to extract zip file using python

ZipFile.extractall(path=None, members=None, pwd=None)

Source: thispointer.com

Similar codes

1 vote162 views1 answer
Delimiter pandas
Python
5 votes167 views3 answers
Print complete dataframe pandas
Python
0 vote236 views1 answer
Template tag django
Python Django
0 vote182 views1 answer
Python look for image on screen
Python
1 vote211 views1 answer
How to make a discord bot dm someone python
Python
0 vote175 views1 answer
Search bar using python
Python
0 vote247 views1 answer
How to install neat
Python
0 vote170 views1 answer
Python pass string with spaces as argument
Python
5 votes256 views3 answers
ImportError: No module named flask
Python Flask
0 vote173 views1 answer
Show pythonpath
Python