/Python/Python extract zip file without directory structure

Python extract zip file without directory structure

Python zip extract directory

import zipfile

archive = zipfile.ZipFile('archive.zip')

for file in archive.namelist():
    if file.startswith('foo/'):
        archive.extract(file, 'destination_path')

Source: stackoverflow.com

Python extract zip file without directory structure

import os
import shutil
import zipfile

my_dir = r"D:\Download"
my_zip = r"D:\Download\my_file.zip"

with zipfile.ZipFile(my_zip) as zip_file:
    for member in zip_file.namelist():
        filename = os.path.basename(member)
        # skip directories
        if not filename:
            continue

        # copy file (taken from zipfile's extract)
        source = zip_file.open(member)
        target = open(os.path.join(my_dir, filename), "wb")
        with source, target:
            shutil.copyfileobj(source, target)

Source: stackoverflow.com

How to extract zip file using python

ZipFile.extractall(path=None, members=None, pwd=None)

Source: thispointer.com

Similar codes

11 votes148 views2 answers
Pandas shuffle rows
Python
0 vote146 views1 answer
Python import colors
Python
0 vote155 views1 answer
Python with braces
Python
0 vote139 views1 answer
Python replace list from another dictionary items
Python
0 vote183 views1 answer
How to numbered jupyter notebook
Python
6 votes177 views2 answers
Flask get ip address of request
Python Flask
0 vote138 views1 answer
Pandas rearrange rows based on datetime index
Python
17 votes152 views6 answers
Odd or even in python
Python
0 vote93 views1 answer
Python which __divs__ are there
Python
8 votes131 views3 answers
Print traceback python
Python