/Python/Python extract zip file without directory structure

Python extract zip file without directory structure

Python zip extract directory

import zipfile

archive = zipfile.ZipFile('archive.zip')

for file in archive.namelist():
    if file.startswith('foo/'):
        archive.extract(file, 'destination_path')

Source: stackoverflow.com

Python extract zip file without directory structure

import os
import shutil
import zipfile

my_dir = r"D:\Download"
my_zip = r"D:\Download\my_file.zip"

with zipfile.ZipFile(my_zip) as zip_file:
    for member in zip_file.namelist():
        filename = os.path.basename(member)
        # skip directories
        if not filename:
            continue

        # copy file (taken from zipfile's extract)
        source = zip_file.open(member)
        target = open(os.path.join(my_dir, filename), "wb")
        with source, target:
            shutil.copyfileobj(source, target)

Source: stackoverflow.com

How to extract zip file using python

ZipFile.extractall(path=None, members=None, pwd=None)

Source: thispointer.com

Similar codes

1 vote181 views2 answers
Flask socketio send
Python Flask
79 votes160 views3 answers
Metronome
Python
4 votes128 views2 answers
Selenium python maximize window
Python
0 vote133 views1 answer
String maniupulation in python
Python
2 votes157 views1 answer
Pandas remame a no name column
Python
1 vote159 views1 answer
Like in mysqldb python
Python
8 votes158 views3 answers
Which python mac
Python
0 vote156 views1 answer
Python filter timestamp
Python
3 votes130 views2 answers
Wikipedia python
Python
6 votes155 views3 answers
Example images
Python