Df.loc

Pandas loc for list

df.loc[df['channel'].isin(['sale','fullprice'])]

Source: stackoverflow.com

Df.loc

# Getting values on a DataFrame with an index that has interger "labels"
df = pd.DataFrame([[1, 2], [4, 5], [7, 8]],
...      index=[7, 8, 9], columns=['max_speed', 'shield'])
>>> df
   max_speed  shield
7          1       2
8          4       5
9          7       8

# the integer is interpreted as "label" but NOT an "interger position along the index"
>>> df.loc[7:9]
   max_speed  shield
7          1       2
8          4       5
9          7       8

Source: pandas.pydata.org

Similar codes

1 vote209 views2 answers
Ast python
Python
62 votes206 views5 answers
How to pick a random number in a list python
Python
0 vote258 views1 answer
Django admin no such table user
Python Django
0 vote227 views1 answer
How to initialize pygame
Python
1 vote311 views1 answer
Add search field to django admin
Python Django
8 votes188 views2 answers
Inverse matrice python
Python
0 vote239 views1 answer
Visitor IP address django
Python Django
22 votes260 views6 answers
String palindrome in python
Python
16 votes208 views3 answers
How to change the column order in pandas dataframe
Python
1 vote201 views1 answer
How to print time python 3
Python