/Python/How to filter out all NaN values in pandas df

How to filter out all NaN values in pandas df

Drop if nan in column pandas

df = df[df['EPS'].notna()]

Pandas drop rows with nan in a particular column

In [30]: df.dropna(subset=[1])   #Drop only if NaN in specific column (as asked in the question)
Out[30]:
          0         1         2
1  2.677677 -1.466923 -0.750366
2       NaN  0.798002 -0.906038
3  0.672201  0.964789       NaN
5 -1.250970  0.030561 -2.678622
6       NaN  1.036043       NaN
7  0.049896 -0.308003  0.823295
9 -0.310130  0.078891       NaN

Source: stackoverflow.com

How to filter out all NaN values in pandas df

#return a subset of the dataframe where the column name value != NaN 
df.loc[df['column name'].isnull() == False]

Python remove nan rows

df = df[df['my_var'].notna()]

Source: stackoverflow.com

When converting from dataframe to list delete nan values

a = [[y for y in x if pd.notna(y)] for x in df.values.tolist()]
print (a)
[['str', 'aad', 'asd'], ['ddd'], ['xyz', 'abc'], ['btc', 'trz', 'abd']]

Source: stackoverflow.com

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