How to make a window in pyga,e

import pygame
pygame.init()
screen = pygame.display.set_mode((700, 500))
pygame.display.set_caption('Prototype_1')
carryOn = True
while carryOn:
	for event in pygame.events.get():
		if event.type == pygame.QUIT:  # If user clicked close
        	CarryOn = False  # Flag that we are done so we exit this loop
            print("we should be closing now!")
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_x:  # Pressing the x Key will quit the game
                CarryOn = False
            print("we should be closing now")

pygame.quit()

Similar codes

12 votes107 views2 answers
Python how to return max num index
Python
26 votes98 views5 answers
Python square root
Python
0 vote93 views1 answer
Genrate random code in django
Python
-1 vote105 views1 answer
Significant figures on axes plot matplotlib
Python
0 vote105 views1 answer
Convert file to base64 python
Python
1 vote105 views1 answer
Python WSGI server
Python
0 vote107 views2 answers
Flask conditional according to urrl
Python
0 vote103 views1 answer
How to delete all instances of a model in django
Python
51 votes101 views6 answers
Open and read a file in python
Python
31 votes100 views6 answers
Round off python
Python