/Python/Cyclically rotate an array by one

Cyclically rotate an array by one

def rotate( arr, n):
    a[0],a[1:]=a[-1],a[:n-1]
    
#Driver Code    
a=[-1,2,3,7,5]
rotate(a,len(a))
print(a)
#Output: [5, -1, 2, 3, 7]

Cyclically rotate an array by one

# Python3 code for program to
# cyclically rotate an array by one
 
# Method for rotation
def rotate(arr, n):
    x = arr[n - 1]
     
    for i in range(n - 1, 0, -1):
        arr[i] = arr[i - 1];
         
    arr[0] = x;
 
 
# Driver function
arr= [1, 2, 3, 4, 5]
n = len(arr)
print ("Given array is")
for i in range(0, n):
    print (arr[i], end = ' ')
 
rotate(arr, n)
 
print ("\nRotated array is")
for i in range(0, n):
    print (arr[i], end = ' ')
 
# This article is contributed
# by saloni1297

Source: geeksforgeeks.org

Similar codes

0 vote168 views1 answer
Recorrer diccionario python
Python
0 vote135 views1 answer
List tuple dictionary,
Python
0 vote137 views1 answer
Python list pop equivalent
Python
0 vote191 views1 answer
Program to add first and last digit of a number in python
Python
1 vote216 views2 answers
Django content type
Python Django
1 vote151 views1 answer
ModuleNotFoundError: No module named 'transforms3d'
Python
1 vote153 views1 answer
ANSHUL
Python
-1 vote136 views1 answer
Car python program
Python
0 vote148 views3 answers
Python compiler to c++
Python
11 votes153 views5 answers
Python ordereddict
Python