/Python/Python 3 define type in arguments with default value

Python 3 define type in arguments with default value

Python 3 define type in arguments with default value

def foo(opts: dict = {}):
    pass

print(foo.__annotations__)

0

Source: stackoverflow.com

Similar codes

0 vote133 views1 answer
Create pytorch zeros
Python
0 vote129 views1 answer
How make aloop in python
Python
0 vote140 views1 answer
Keras.datasets no module
Python
0 vote129 views1 answer
Python file hidden
Python
16 votes127 views1 answer
Python reimport py file
Python
0 vote172 views1 answer
Get last save id django model
Python Django
0 vote126 views1 answer
Python initialise list of lists
Python
0 vote153 views1 answer
Michelin primacy 4
Python
1 vote119 views1 answer
Tkinter listbox delete all items
Python
0 vote121 views1 answer
Django custome login
Python

Share