/Python/Sort list of dictionaries python by value

Sort list of dictionaries python by value

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

How to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

Python sort a dictionary by values

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Python sort array of dictionary by value

my_list = sorted(my_list, key=lambda k: k['name'])

Source: stackoverflow.com

Similar codes

0 vote193 views1 answer
Open link in tab new trong selenium python
Python
0 vote202 views1 answer
Ello
Python
0 vote244 views1 answer
Rename dataframe index column pandas
Python
15 votes201 views6 answers
Python list max value
Python
1 vote198 views1 answer
Return result from exec python
Python
0 vote205 views1 answer
Limpiar consola en python
Python
1 vote138 views1 answer
What is .new() is used in python
Python
0 vote242 views1 answer
Def get_label(Dir): for nextdir in os.listdir(Dir): if not nextdir.startswith('.'): if nextdir in ['NORMAL']: label = 0 elif nextdir in ['PNEUMONIA']: label = 1 else: label = 2 return nextdir, label
Python
51 votes196 views4 answers
Online python compiler with all modules
Python
0 vote196 views1 answer
Clahe opencv
Python