/Python/Sort list of dictionaries python by value

Sort list of dictionaries python by value

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

How to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

Python sort a dictionary by values

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Python sort array of dictionary by value

my_list = sorted(my_list, key=lambda k: k['name'])

Source: stackoverflow.com

Similar codes

0 vote139 views1 answer
Full dist upgrade kali
Python
0 vote149 views2 answers
Merge two sorted lists into one sorted list
Python
8 votes146 views3 answers
Python execute function from string
Python
3 votes161 views2 answers
Venv upgrade python
Python
0 vote148 views1 answer
Python split paragraph
Python
28 votes147 views3 answers
How to know if a string is a number python
Python
0 vote153 views1 answer
Python selenium for desktop application
Python
0 vote173 views1 answer
Pandas series draw distribution
Python
0 vote145 views1 answer
# Import KNeighborsClassifier from sklearn.neighbors
Python
33 votes125 views4 answers
Sort and reverse list in python
Python