Php try json decode

Php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Php try json decode

/** Checks if JSON and returns decoded as an array, if not, returns false, 
but you can pass the second parameter true, if you need to return
a string in case it's not JSON */
function tryJsonDecode($string, $returnString = false) {
   $arr = json_decode($string);
  if (json_last_error() === JSON_ERROR_NONE) {
    return $arr;
  } else {
    return ($returnString) ? $string : false;
  }
}

Php try json decode and check

// Checks if json
function isJson($string) {
   json_decode($string);
   return json_last_error() === JSON_ERROR_NONE;
}

// example
if (isJson($string) {
  // Do your stuff here
}

-1

Similar codes

0 vote159 views1 answer
Codeigniter sms send
PHP
47 votes184 views4 answers
Substr() php
PHP
0 vote185 views3 answers
Laravel get all records order by
PHP Laravel
12 votes194 views6 answers
Return redirect with message laravel
PHP Laravel
0 vote198 views1 answer
Padding number in php
PHP
1 vote107 views2 answers
Route [/login] not defined.
PHP
0 vote160 views1 answer
Php gd coordinate
PHP
0 vote170 views1 answer
Php interview questions for experience
PHP
0 vote190 views1 answer
Delete image s3 laravel
PHP
0 vote177 views1 answer
Php get final redirect url
PHP