Php try json decode

Php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Php try json decode

/** Checks if JSON and returns decoded as an array, if not, returns false, 
but you can pass the second parameter true, if you need to return
a string in case it's not JSON */
function tryJsonDecode($string, $returnString = false) {
   $arr = json_decode($string);
  if (json_last_error() === JSON_ERROR_NONE) {
    return $arr;
  } else {
    return ($returnString) ? $string : false;
  }
}

Php try json decode and check

// Checks if json
function isJson($string) {
   json_decode($string);
   return json_last_error() === JSON_ERROR_NONE;
}

// example
if (isJson($string) {
  // Do your stuff here
}

-1

Similar codes

0 vote139 views1 answer
If certain condition is met exit if block php
PHP
6 votes147 views5 answers
Phpinfo file
PHP
1 vote160 views2 answers
Laravel update email unique
PHP Laravel
0 vote141 views1 answer
Disable display error
PHP
0 vote157 views1 answer
Run phpcs from vs code for wordpress
PHP Wordpress
0 vote144 views1 answer
How condition for multiple row by orwhere laravel
PHP
0 vote168 views1 answer
Laravel model relationships with two columns match
PHP Laravel
1 vote141 views2 answers
Check duplicate data in array php
PHP
0 vote147 views1 answer
Symfony add field to entity
PHP
-1 vote141 views2 answers
Adminlte 3 laravel
PHP