/TypeScript/Get arguments from url flask

Get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

Source: stackoverflow.com

Flask get with parameters

from flask import request

@app.route('/my-route')
def my_route():
  page = request.args.get('page', default = 1, type = int)
  filter = request.args.get('filter', default = '*', type = str)

Source: stackoverflow.com

Similar codes

1 vote134 views1 answer
Get all documents in collection firestore flutter
TypeScript
0 vote166 views1 answer
Ht office
TypeScript
0 vote146 views1 answer
Difference in minutes between 2 time inputs laravel
TypeScript
0 vote174 views1 answer
Choose random elements from vector without repetition and adding to another vector c++
TypeScript
0 vote137 views1 answer
Pass command line arguments C#
TypeScript
0 vote147 views1 answer
How-do-i-navigate-to-a-parent-route-from-a-child-route
TypeScript
0 vote144 views1 answer
Run a python module with imports from parent
TypeScript
-2 votes150 views6 answers
Eval)free robux 17k
TypeScript
1 vote175 views2 answers
No type arguments expected for interface ListAdapter
TypeScript
0 vote231 views1 answer
Factory design pattern typescript
TypeScript