/TypeScript/Get arguments from url flask

Get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

Source: stackoverflow.com

Flask get with parameters

from flask import request

@app.route('/my-route')
def my_route():
  page = request.args.get('page', default = 1, type = int)
  filter = request.args.get('filter', default = '*', type = str)

Source: stackoverflow.com

Similar codes

32 votes178 views1 answer
Ng : File C:\Users\nEW u\AppData\Roaming\npm\ng.ps1 cannot be loaded. The file C:\Users\nEW u\AppData\Roaming\npm\ng.ps1 is setting execution policy, see about_Execution_Policies at https:/go.microsoft.com/fwlink/?LinkID=135170. At line:1 char:1
TypeScript
1 vote200 views1 answer
React Native: Double back press to Exit App
TypeScript
1 vote177 views1 answer
:= and = in gdscript
TypeScript
0 vote175 views1 answer
Conventional commits cheat sheet
TypeScript
0 vote186 views1 answer
Loc multiple conditions string and integer
TypeScript
0 vote191 views1 answer
How to show account related contacts on click of a button using lightnig components
TypeScript
0 vote175 views1 answer
Google sheets mode text
TypeScript
1 vote184 views1 answer
Python requests use many proxy
TypeScript
1 vote183 views1 answer
Is assigned a value but never used
TypeScript
0 vote182 views2 answers
Spritesheets in pyqt
TypeScript