/TypeScript/Get arguments from url flask

Get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

Source: stackoverflow.com

Flask get with parameters

from flask import request

@app.route('/my-route')
def my_route():
  page = request.args.get('page', default = 1, type = int)
  filter = request.args.get('filter', default = '*', type = str)

Source: stackoverflow.com

Similar codes

1 vote101 views1 answer
How to move data between request
TypeScript
-1 vote113 views1 answer
Fwrite() expects parameter 2 to be string, array given
TypeScript
0 vote103 views1 answer
Code solutions online for public IActionResult Student() { return View(Students Controller 1); }
TypeScript
0 vote97 views1 answer
Dart check if variable is list
TypeScript
0 vote101 views1 answer
How to disable form control but keep value
TypeScript
0 vote109 views1 answer
React full calendar
TypeScript
0 vote103 views2 answers
Reactive forms radio button
TypeScript
0 vote102 views2 answers
Giving arguments to main function in c
TypeScript
9 votes101 views4 answers
Combine list of lists python
TypeScript
0 vote111 views1 answer
Correct this attempt to modify "product" or use "let" in its declaration. [+1 location]
TypeScript