Pandas df by row index

indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]

Retrieve row by index pandas

rowData = dfObj.loc[ 'b' , : ]

Source: thispointer.com

Dataframe select row by index value

In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))

In [2]: df
Out[2]: 
          A         B
0  1.068932 -0.794307
2 -0.470056  1.192211
4 -0.284561  0.756029
6  1.037563 -0.267820
8 -0.538478 -0.800654

In [5]: df.iloc[[2]]
Out[5]: 
          A         B
4 -0.284561  0.756029

In [6]: df.loc[[2]]
Out[6]: 
          A         B
2 -0.470056  1.192211

Source: stackoverflow.com

Similar codes

-1 vote133 views1 answer
Google codelabs
Python
0 vote158 views1 answer
Django queryset all objects
Python Django
10 votes163 views2 answers
Django import settings
Python Django
1 vote128 views2 answers
Python any in string
Python
-1 vote129 views2 answers
Split long list into chunks of 100
Python
3 votes168 views1 answer
Import py to exe
Python
0 vote108 views1 answer
How to resize image with pillow in django
Python Django
145 votes126 views5 answers
Create file python
Python
57 votes123 views6 answers
Python get list of files in directory
Python
0 vote120 views1 answer
How to print stdout while processing the execution in python
Python