How to get size of array c++

Array length c++

#include <iostream>
using namespace std;

#define size(type) ((char *)(&type+1)-(char*)(&type))

int main(){
  int arr[5] = {1, 2, 3, 4, 5};
  cout << size(arr) / size(arr[0]) << endl; //returns 5
  //alternatively
  cout << sizeof(arr) / sizeof(int) << endl; //returns 5
}

Find length of array c++

#include <iostream>
using namespace std;
int main() {
   int arr[5] = {4, 1, 8, 2, 9};
   int len = sizeof(arr)/sizeof(arr[0]);
   cout << "The length of the array is: " << len;
   return 0;
}

Array length c++

// array::size
#include <iostream>
#include <array>

int main ()
{
  std::array<int,5> myints;
  std::cout << "size of myints: " << myints.size() << std::endl;
  std::cout << "sizeof(myints): " << sizeof(myints) << std::endl;

  return 0;
}

Source: cplusplus.com

Length of array in cpp

int size = sizeof(arr)/sizeof(arr[0])

How to find size of int array in c++

#include <iostream>
using namespace std;

int main() {
	int arr[] = {10,20,30,40,50,60};
	int arrSize = sizeof(arr)/sizeof(arr[0]);
	cout << "The size of the array is: " << arrSize;
	return 0;
{

How to get size of array c++

put in something

-4

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