Rails array pop first n elements

Ruby pop array

a = [1, 2, 3, 4]
a.pop()
# => 4

Rails array pop first n elements

array = [1, 2, 3, 4, 5, 6]
array.drop(2)

# => [3, 4, 5, 6]

Ruby exclude from slice

# First of all you have to use splat (*) operator. 
# Then instead of using .slice() and .except() together, you can do this is more efficient way.

columns_to_show = ['age', 'gender', 'cast', 'fee_status']
columns_to_show = columns_to_show - hidden_columns if hidden_columns

patient.slice(*columns_to_show).values

patient.slice('age', 'gender', 'cast', 'fee_status').except(*hidden_columns)
 => {"cast"=>"black", "fee_status"=>"paid"}

Source: stackoverflow.com

Similar codes

0 vote178 views1 answer
How to create a database in production mode rails
Ruby
0 vote165 views2 answers
Date class to unix timestamp ruby
Ruby
0 vote160 views1 answer
Logstash-logger gem
Ruby
1 vote178 views1 answer
Ruby filter
Ruby
0 vote169 views10 answers
How to get every question right on ixl
Ruby
0 vote194 views1 answer
Ruby sort an object
Ruby
1 vote177 views2 answers
New line in ruby
Ruby
0 vote188 views1 answer
Ruby sinatra helper
Ruby
0 vote237 views1 answer
Rails .map unless nil
Ruby
1 vote173 views1 answer
Getting wanked off by ruby
Ruby