Django reverse

from django.urls import reverse

def myview(request):
    return HttpResponseRedirect(reverse('arch-summary', args=[1945]))

Source: docs.djangoproject.com

Django reverse

return HttpResponseRedirect(reverse('blogIndex', args=[str(pk)]))

Django reverse lazy

class NewJobCBV(LoginRequiredMixin, CreateView):
    template_name = 'company/job.html'
    form_class = newJobForm
    # success_url = reverse_lazy('newJob')

    def get_success_url(self, **kwargs):
        return reverse("newJob")

-2

Source: stackoverflow.com

Similar codes

0 vote137 views1 answer
Create bootable usb apple
Python
3 votes169 views1 answer
Pandas filter non nan
Python
1 vote138 views1 answer
How to create obtain any random 3 items of list in python
Python
4 votes149 views4 answers
Bar chart in python
Python
1 vote168 views1 answer
How to make a discord bot dm someone python
Python
0 vote135 views1 answer
Streaming upload requests python
Python
0 vote156 views1 answer
How to change defaul tpython version\
Python
0 vote138 views2 answers
Html to docx python
Python
0 vote165 views1 answer
Python how to print something at a specific place
Python
1 vote107 views2 answers
Alpaca api python wrapper
Python