Even in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Python even or odd

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

Even in python

if (num % 2) == 0:

Similar codes

0 vote147 views1 answer
Remove scientific notation python matplotlib
Python
0 vote150 views1 answer
What does -> none do in python
Python
0 vote175 views1 answer
Python pil get pixel
Python
0 vote166 views1 answer
Python console
Python
0 vote174 views6 answers
Django wht post save signal not firing
Python
2 votes185 views2 answers
Django response headers
Python Django
1 vote148 views1 answer
Get_or_create in django
Python
0 vote171 views1 answer
Python import colors
Python
2 votes167 views1 answer
How to load ui file in pyqt5
Python
0 vote154 views1 answer
How to get scrapy output file in xml file
Python