Pandas select column by index

Select columns pandas

df1 = df.iloc[:,0:2] # Remember that Python does not slice inclusive of the ending index.

Source: stackoverflow.com

Pandas select column by index

#    A  B  C
# 0  1  3  5
# 1  2  4  6

column_B = a_dataframe.iloc[:, 1]
print(column_B)

# OUTPUT
# 0    3
# 1    4

Source: kite.com

Select rows from dataframe pandas

from pandas import DataFrame

boxes = {'Color': ['Green','Green','Green','Blue','Blue','Red','Red','Red'],
         'Shape': ['Rectangle','Rectangle','Square','Rectangle','Square','Square','Square','Rectangle'],
         'Price': [10,15,5,5,10,15,15,5]
        }

df = DataFrame(boxes, columns= ['Color','Shape','Price'])

select_color = df.loc[df['Color'] == 'Green']
print (select_color)

Source: datatofish.com

Retrieve row by index pandas

rowData = dfObj.loc[ 'b' , : ]

Source: thispointer.com

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