Php difference between two dates

Php calculate date difference

//get Date diff as intervals 
$d1 = new DateTime("2018-01-10 00:00:00");
$d2 = new DateTime("2019-05-18 01:23:45");
$interval = $d1->diff($d2);
$diffInSeconds = $interval->s; //45
$diffInMinutes = $interval->i; //23
$diffInHours   = $interval->h; //8
$diffInDays    = $interval->d; //21
$diffInMonths  = $interval->m; //4
$diffInYears   = $interval->y; //1

//or get Date difference as total difference
$d1 = strtotime("2018-01-10 00:00:00");
$d2 = strtotime("2019-05-18 01:23:45");
$totalSecondsDiff = abs($d1-$d2); //42600225
$totalMinutesDiff = $totalSecondsDiff/60; //710003.75
$totalHoursDiff   = $totalSecondsDiff/60/60;//11833.39
$totalDaysDiff    = $totalSecondsDiff/60/60/24; //493.05
$totalMonthsDiff  = $totalSecondsDiff/60/60/24/30; //16.43
$totalYearsDiff   = $totalSecondsDiff/60/60/24/365; //1.35

Date diff php

$datetime1 	= new DateTime('2020-10-11 16:52:52');
$datetime2 	= new DateTime('2020-10-13 16:52:52');
$interval 	= $datetime1->diff($datetime2);

echo $interval->format('%a days');

Php get day diff

$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;

echo round($datediff / (60 * 60 * 24));

Source: stackoverflow.com

Calculate the Difference Between Two Dates Using PHP

$firstDate = "2019-01-01";
$secondDate = "2020-03-04";

$dateDifference = abs(strtotime($secondDate) - strtotime($firstDate));

$years  = floor($dateDifference / (365 * 60 * 60 * 24));
$months = floor(($dateDifference - $years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));
$days   = floor(($dateDifference - $years * 365 * 60 * 60 * 24 - $months * 30 * 60 * 60 *24) / (60 * 60 * 24));

echo $years." year,  ".$months." months and ".$days." days";

//output: 1 year, 2 months and 3 days

Difference of two dates in seconds php

$timeFirst  = strtotime('2011-05-12 18:20:20');
$timeSecond = strtotime('2011-05-13 18:20:20');
$differenceInSeconds = $timeSecond - $timeFirst;

Source: stackoverflow.com

Php difference between two dates

$date1 = "2007-03-24";
$date2 = "2009-06-26";

$diff = abs(strtotime($date2) - strtotime($date1));

$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

printf("%d years, %d months, %d days\n", $years, $months, $days);

Source: stackoverflow.com

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