/TypeScript/Get url params in typescript

Get url params in typescript

import {Router, ActivatedRoute, Params} from '@angular/router';
import {OnInit, Component} from '@angular/core';

@Component({...})
export class MyComponent implements OnInit {

  constructor(private activatedRoute: ActivatedRoute) {}

  ngOnInit() {
    // Note: Below 'queryParams' can be replaced with 'params' depending on your requirements
    this.activatedRoute.queryParams.subscribe(params => {
        const userId = params['userId'];
        console.log(userId);
      });
  }

}

Source: stackoverflow.com

Similar codes

0 vote149 views1 answer
Allow specific string in type
TypeScript
1 vote186 views2 answers
Benefits of linux
TypeScript
0 vote199 views1 answer
What is use hsts in .net core
TypeScript
1 vote237 views1 answer
Useappselector
TypeScript
0 vote213 views1 answer
Mat-toolbar' is not a known element
TypeScript
1 vote219 views1 answer
Node fetch exports is not defined
TypeScript
0 vote192 views1 answer
How to parameterize test cases
TypeScript
0 vote197 views1 answer
Route.component does not have any construct or call signatures - React Router with TypeScript
TypeScript
1 vote183 views1 answer
Smooth scroll in viewportscroller
TypeScript
2 votes189 views1 answer
Aws sts assume-role example
TypeScript