Replace nan numpy array

Python numpy array replace nan with string

import numpy as np
l=['foo', 'bar', 'baz', np.nan]

l_new=['missing' if x is np.nan else x for x in l]

print l_new
# Result:
# ['foo', 'bar', 'baz', 'missing']

Source: stackoverflow.com

Replace nan numpy array

from numpy import *

a = array([[1, 2, 3], [0, 3, NaN]])
where_are_NaNs = isnan(a)
a[where_are_NaNs] = 0

Source: stackoverflow.com

Similar codes

8 votes121 views1 answer
Convert column string to int pandas
Python
3 votes147 views1 answer
Django flush
Python Django
3 votes133 views2 answers
Button images in tkinter
Python
0 vote127 views1 answer
Printing a varible with a varible. python
Python
0 vote126 views1 answer
Python for loop in range 01 02
Python
2 votes121 views1 answer
Python how to unnest a nested list
Python
0 vote135 views1 answer
Pretty print list python
Python
0 vote149 views1 answer
Docker opencv python libGL.so.1: cannot open shared object file: No such file or directory
Python
6 votes88 views1 answer
Business logic in django
Python
9 votes119 views7 answers
Print python
Python