Replace nan numpy array

Python numpy array replace nan with string

import numpy as np
l=['foo', 'bar', 'baz', np.nan]

l_new=['missing' if x is np.nan else x for x in l]

print l_new
# Result:
# ['foo', 'bar', 'baz', 'missing']

Source: stackoverflow.com

Replace nan numpy array

from numpy import *

a = array([[1, 2, 3], [0, 3, NaN]])
where_are_NaNs = isnan(a)
a[where_are_NaNs] = 0

Source: stackoverflow.com

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